(x^2+400x)/2000=0

Solution for (x^2+400x)/2000=0 equation:

(x^2+400x)/2000=0

We multiply all the terms by the denominator


(x^2+400x)=0

We get rid of parentheses

x^2+400x=0

a = 1; b = 400; c = 0;
Δ = b2-4ac
Δ = 4002-4·1·0
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-400}{2*1}=\frac{-800}{2}
=-400
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+400}{2*1}=\frac{0}{2}
=0
$